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Sam purchased a new car for [tex]$\$ 17,930$[/tex]. The value of the car depreciated by [tex]$19 \%$[/tex] per year. When he trades the car in after [tex]$x[tex]$[/tex] years, the car is worth no more than [tex]$[/tex]\$ 1,900$[/tex].

Fill in the values of [tex][tex]$a, b$[/tex][/tex], and [tex]$c$[/tex] to complete the exponential inequality of the form [tex]$a(b)^x \leq c$[/tex] that can be used to determine the number of years after which the car is worth no more than [tex][tex]$\$[/tex] 1,900$[/tex].

[tex]a(b)^x \leq c[/tex]



Answer :

Given the problem, the situation can be formulated into an exponential inequality as [tex]\( a(b)^x \leq c \)[/tex]. Here's how to assign the values to [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex]:

- Initial value of the car, [tex]\( a \)[/tex]: Sam purchased the car for \[tex]$17,930, so \( a = 17,930 \). - Depreciation factor, \( b \): The car depreciates by 19% each year, leaving it with 81% of its value from the previous year. This means \( b = 0.81 \). - Value after \( x \) years, \( c \): The car's worth should not exceed \$[/tex]1,900 after [tex]\( x \)[/tex] years, so [tex]\( c = 1,900 \)[/tex].

Filling in these values, the inequality becomes:

[tex]\[ 17,930 \cdot (0.81)^x \leq 1,900 \][/tex]

Thus, in the form [tex]\( a(b)^x \leq c \)[/tex]:

- [tex]\( a = 17,930 \)[/tex]
- [tex]\( b = 0.81 \)[/tex]
- [tex]\( c = 1,900 \)[/tex]

So the completed exponential inequality is:

[tex]\[ 17,930 \cdot (0.81)^x \leq 1,900 \][/tex]