A mixture of three noble gases has a total pressure of 1.25 atm. The individual pressures exerted by neon and argon are 0.68 atm and 0.35 atm, respectively. What is the partial pressure of the third gas, helium? Use [tex]P_T = P_1 + P_2 + P_3 + \ldots + P_n[/tex].

A. 0.22 atm
B. 0.33 atm
C. 1.03 atm
D. 2.28 atm



Answer :

Alright class, let's solve this problem step-by-step using the information provided and the formula for the total pressure of a gas mixture, [tex]\( P_T = P_1 + P_2 + P_3 + \ldots + P_n \)[/tex].

Step 1: Identify the given values

We are given:
- The total pressure of the gas mixture, [tex]\( P_T \)[/tex], is 1.25 atm.
- The partial pressure of neon, [tex]\( P_{Ne} \)[/tex], is 0.68 atm.
- The partial pressure of argon, [tex]\( P_{Ar} \)[/tex], is 0.35 atm.

Step 2: Write down the formula

The formula for the total pressure of a mixture of gases is:
[tex]\[ P_T = P_{Ne} + P_{Ar} + P_{He} \][/tex]

Step 3: Substitute the known values into the formula

We know the total pressure and the partial pressures of neon and argon:
[tex]\[ 1.25 \text{ atm} = 0.68 \text{ atm} + 0.35 \text{ atm} + P_{He} \][/tex]

Step 4: Solve for the unknown, [tex]\( P_{He} \)[/tex]

First, add the partial pressures of neon and argon:
[tex]\[ 0.68 \text{ atm} + 0.35 \text{ atm} = 1.03 \text{ atm} \][/tex]

Next, subtract this sum from the total pressure to find the partial pressure of helium:
[tex]\[ P_{He} = 1.25 \text{ atm} - 1.03 \text{ atm} \][/tex]

Step 5: Perform the subtraction

[tex]\[ P_{He} = 0.22 \text{ atm} \][/tex]

So, the partial pressure of helium in the mixture is [tex]\( 0.22 \)[/tex] atm.

Thus, the correct answer from the given options is:

[tex]\[ \boxed{0.22 \text{ atm}} \][/tex]