A man walks west for 500 feet, then turns and walks at an angle of [tex]$52^{\circ}$[/tex] south of west for 371 feet. What is the direction of the man's resultant vector?

[tex]\[
\begin{array}{c}
|\vec{R}| = 784.89 \text{ feet} \\
\theta = [?]^{\circ}
\end{array}
\][/tex]

Round your answer to the nearest hundredth.



Answer :

Certainly! Let's solve the problem step-by-step to find the direction of the man's resultant vector given that he walks 500 feet west and then 371 feet at an angle of [tex]\(52^\circ\)[/tex] south of west.

1. Set up the problem with components:

- When the man walks 500 feet west, he travels purely in the west direction.
- For the second part of his walk, he travels at an angle of [tex]\(52^\circ\)[/tex] south of west for 371 feet.

2. Convert the angle to the usual coordinate system:

- South of west means we can break this into west and south components.
- Let's decompose the 371 feet into westward and southward components using trigonometry.

3. Calculate the westward (x) and southward (y) components:

- For the westward component:
[tex]\[ \text{West component} = 371 \cdot \cos(52^\circ) \][/tex]
- For the southward component:
[tex]\[ \text{South component} = 371 \cdot \sin(52^\circ) \][/tex]

4. Sum the total westward and southward components:

- Total westward distance:
[tex]\[ R_x = 500 + 371 \cdot \cos(52^\circ) \][/tex]
- Total southward distance:
[tex]\[ R_y = 371 \cdot \sin(52^\circ) \][/tex]

5. Use these components to determine the angle [tex]\( \theta \)[/tex] of the resultant vector:

- The angle [tex]\( \theta \)[/tex] with respect to the west direction (clockwise from west):
[tex]\[ \theta = \arctan\left(\frac{R_y}{R_x}\right) \][/tex]
- To find the direction bearing from the west:
[tex]\[ \theta = 180^\circ - \theta \][/tex]

6. Calculate the direction:

The detailed steps give us the value:
[tex]\[ \theta = 158.13^\circ \][/tex]

So, after rounding to the nearest hundredth, the direction of the man's resultant vector is:

[tex]\[ \boxed{158.13^\circ} \][/tex]