When the focus and directrix are used to derive the equation of a parabola, two distances are set equal to each other.

[tex]$
\sqrt{(x - x)^2 + (y - (-p))^2} = \sqrt{(x - 0)^2 + (y - p)^2}
$[/tex]

The distance between the directrix and any point on the parabola is set equal to the distance between the focus and the same point on the parabola.



Answer :

To derive the equation of a parabola, we begin by setting two distances equal to each other as given:

[tex]\[ \sqrt{(x - x)^2 + (y - (-p))^2} = \sqrt{(x - 0)^2 + (y - p)^2} \][/tex]

The important things to note here are the definitions of focus and directrix:

1. Focus: The fixed point [tex]\((x, -p)\)[/tex].
2. Directrix: The fixed line, in this case, represented by [tex]\(y = p\)[/tex].

For a point [tex]\((x, y)\)[/tex] on the parabola, we compare:
1. The distance from this point to the focus.
2. The distance from this point to the directrix.

Now, the given equation showcases the equal distances setup:

1. Distance between the point [tex]\((x, y)\)[/tex] and the focus [tex]\((0, -p)\)[/tex]:

[tex]\[ \sqrt{(x - 0)^2 + (y - (-p))^2} = \sqrt{x^2 + (y + p)^2} \][/tex]

2. Distance between the point [tex]\((x, y)\)[/tex] and the directrix [tex]\(y = p\)[/tex]:

[tex]\[ \sqrt{(x - x)^2 + (y - p)^2} = \sqrt{(0)^2 + (y - p)^2} = \sqrt{(y - p)^2} \][/tex]

Equating these distances:

[tex]\[ \sqrt{x^2 + (y + p)^2} = \sqrt{(y - p)^2} \][/tex]

Given the setup, we conclude that the distance between the point [tex]\((x, y)\)[/tex] on the parabola and the focus [tex]\((0, -p)\)[/tex] is set equal to the distance between the point [tex]\((x, y)\)[/tex] and the directrix [tex]\(y = p\)[/tex]. These relationships define the characteristic property of a parabola.