The derivation for the equation of a parabola with a vertex at the origin is started below.

[tex]\[ \sqrt{(x-0)^2+(y-p)^2}=\sqrt{(x-x)^2+(y-(-p))^2} \][/tex]

1. [tex]\((x)^2+(y-p)^2=(0)^2+(y+p)^2\)[/tex]
2. [tex]\(x^2+y^2-2 p y+p^2=y^2+2 p y+p^2\)[/tex]

If the equation is further simplified, which equation for a parabola does it become?

A. [tex]\(x^2=4 p y\)[/tex]
B. [tex]\(x^2=2 y^2+2 p^2\)[/tex]
C. [tex]\(y^2=4 p x\)[/tex]
D. [tex]\(y^2=4 p y\)[/tex]



Answer :

Let's continue from where we left off to further simplify the given equation for the parabola:

Given:
[tex]\[ \sqrt{(x-0)^2 + (y-p)^2} = \sqrt{(x-x)^2 + (y-(-p))^2} \][/tex]

Simplify under the square root:
[tex]\[ (x)^2 + (y-p)^2 = (0)^2 + (y+p)^2 \][/tex]

Expand both sides:
[tex]\[ x^2 + y^2 - 2py + p^2 = y^2 + 2py + p^2 \][/tex]

Subtract [tex]\(y^2 + p^2\)[/tex] from both sides:
[tex]\[ x^2 - 2py = 2py \][/tex]

Combine like terms:
[tex]\[ x^2 = 4py \][/tex]

Thus, the equation is simplified to:
[tex]\[ x^2 = 4py \][/tex]

Therefore, the correct equation corresponding to the parabola in the given question is:
[tex]\[ x^2 = 4py \][/tex]