Type the correct answer in each box. Spell all words correctly, and use numerals instead of words for numbers. Use decimal numbers instead of fractions.

The equation [tex]d=3t[/tex] gives the distance, [tex]d[/tex], in meters that Liam swims with respect to time, [tex]t[/tex], in seconds. The table gives the different distances in meters that Edgar swam with respect to time in seconds.

\begin{tabular}{|r|r|}
\hline Time (seconds) & Distance (meters) \\
\hline 20 & 64 \\
\hline 40 & 128 \\
\hline 60 & 192 \\
\hline
\end{tabular}

Assume that Liam and Edgar both swim at a constant rate. On a graph of these relationships, the slope of the line representing the greater rate in terms of distance traveled per unit of time would be:

So, [tex]\square[/tex] swims at a faster rate than [tex]\square[/tex].



Answer :

Determine Liam’s swimming rate by using the equation [tex]\( d = 3t \)[/tex].

The slope of the line representing Liam's swimming rate is calculated as follows:
[tex]\[ \text{Liam's rate} = 3 \, \text{meters per second} \][/tex]

Use the table to calculate Edgar’s swimming rates:

1. When [tex]\( t = 20 \)[/tex] seconds, [tex]\( d = 64 \)[/tex] meters.
[tex]\[ \text{Rate} = \frac{64}{20} = 3.2 \, \text{meters per second} \][/tex]

2. When [tex]\( t = 40 \)[/tex] seconds, [tex]\( d = 128 \)[/tex] meters.
[tex]\[ \text{Rate} = \frac{128}{40} = 3.2 \, \text{meters per second} \][/tex]

3. When [tex]\( t = 60 \)[/tex] seconds, [tex]\( d = 192 \)[/tex] meters.
[tex]\[ \text{Rate} = \frac{192}{60} = 3.2 \, \text{meters per second} \][/tex]

Calculate the average of Edgar's swimming rates:
[tex]\[ \text{Edgar's average rate} = \frac{3.2 + 3.2 + 3.2}{3} = 3.2 \, \text{meters per second} \][/tex]

Compare the swimming rates:

Liam’s rate: [tex]\( 3.0 \)[/tex] meters per second \
Edgar’s average rate: [tex]\( 3.2 \)[/tex] meters per second

Since [tex]\( 3.2 > 3.0 \)[/tex], Edgar swims at a faster rate than Liam.

So, the correct answer to fill the boxes is:
Edgar swims at a faster rate than Liam