Given the following equation, simplify and verify the trigonometric identity:
[tex]\[1 = \sec \beta \cdot \cos \beta\][/tex]



Answer :

Sure, let's analyze the equation [tex]\( 1 = \sec(\beta) \cdot \cos(\beta) \)[/tex].

Step 1: Understand the Trigonometric Identities

First, remember the definition of the secant function. By definition:
[tex]\[ \sec(\beta) = \frac{1}{\cos(\beta)} \][/tex]

Step 2: Substitute the Definition into the Equation

Now, substitute the definition of [tex]\(\sec(\beta)\)[/tex] into the given equation:
[tex]\[ 1 = \sec(\beta) \cdot \cos(\beta) \][/tex]
[tex]\[ 1 = \left( \frac{1}{\cos(\beta)} \right) \cdot \cos(\beta) \][/tex]

Step 3: Simplify the Expression

Next, simplify the right-hand side of the equation. Notice that [tex]\(\frac{1}{\cos(\beta)} \cdot \cos(\beta)\)[/tex] is essentially multiplying a number by its reciprocal:
[tex]\[ 1 = \left( \frac{1}{\cos(\beta)} \right) \cdot \cos(\beta) \][/tex]
[tex]\[ 1 = 1 \][/tex]

Step 4: Conclude the Validity

The equation simplifies to:
[tex]\[ 1 = 1 \][/tex]

Since this statement is always true, it indicates that our original equation:
[tex]\[ 1 = \sec(\beta) \cdot \cos(\beta) \][/tex]
is always true for any value of [tex]\(\beta\)[/tex].

Therefore, the equation [tex]\( 1 = \sec(\beta) \cdot \cos(\beta) \)[/tex] holds true for any value of [tex]\(\beta\)[/tex] where [tex]\(\cos(\beta)\)[/tex] is defined (i.e., [tex]\(\cos(\beta) \neq 0\)[/tex]).