If [tex]$y = 12x - 2$[/tex] were changed to [tex]$y = 12x$[/tex], how would the graph of the new function compare with the original?

A. It would be shifted up.
B. It would be shifted down.
C. It would be less steep.
D. It would be steeper.



Answer :

To understand how the graph of the new function [tex]\( y = 12x \)[/tex] compares with the original function [tex]\( y = 12x - 2 \)[/tex], let's analyze the given functions step-by-step.

1. Original Equation [tex]\( y = 12x - 2 \)[/tex]:
- This is a linear equation of the form [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] is the slope and [tex]\( b \)[/tex] is the y-intercept.
- For [tex]\( y = 12x - 2 \)[/tex]:
- The slope [tex]\( m \)[/tex] is 12.
- The y-intercept [tex]\( b \)[/tex] is -2.
- This means the line crosses the y-axis at [tex]\( (0, -2) \)[/tex] and has a steepness determined by the slope of 12.

2. New Equation [tex]\( y = 12x \)[/tex]:
- This is also a linear equation of the form [tex]\( y = mx + b \)[/tex].
- For [tex]\( y = 12x \)[/tex]:
- The slope [tex]\( m \)[/tex] remains 12.
- The y-intercept [tex]\( b \)[/tex] is now 0.
- This means the line crosses the y-axis at [tex]\( (0, 0) \)[/tex] and maintains the same steepness as before (slope of 12).

3. Comparison:
- Since the slope (12) in both equations is the same, the steepness of the graph does not change.
- The main difference is the y-intercept.
- The y-intercept in the original equation is -2.
- The y-intercept in the new equation is 0.

4. Conclusion:
- The change in the y-intercept from -2 to 0 means that the entire graph is shifted vertically.
- Since 0 is greater than -2, the shift is upwards.

Thus, the correct choice is:

A. It would be shifted up.