To determine the alcohol formed from the hydrolysis of the ester with the formula [tex]\(CH_3CH_2CH_2COOCH_2CH_3\)[/tex], let's go through the process step-by-step to understand how the ester breaks down during hydrolysis.
Hydrolysis of esters generally results in the formation of an alcohol and a carboxylic acid. The ester linkage is typically broken between the oxygen and the carbonyl carbon.
Given the ester: [tex]\(CH_3CH_2CH_2COOCH_2CH_3\)[/tex], we need to identify how it breaks apart:
1. Identify the ester linkage: [tex]\(CH_3CH_2CH_2COOCH_2CH_3\)[/tex].
2. In this ester, the ester bond is between the carbonyl carbon (C=O) on the left side and the oxygen (O) connected to the alkyl group on the right side.
3. During hydrolysis, this bond is cleaved resulting in two separate molecules: an alcohol and a carboxylic acid. The bond breaks between [tex]\(C\)[/tex] and [tex]\(O\)[/tex] of the [tex]\(COO\)[/tex] group.
The ester breaks into the following components:
- The left part becomes a carboxylic acid: [tex]\(CH_3CH_2CH_2COOH\)[/tex].
- The right part becomes an alcohol: [tex]\(CH_3CH_2OH\)[/tex].
Thus, the alcohol formed from the hydrolysis of [tex]\(CH_3CH_2CH_2COOCH_2CH_3\)[/tex] is [tex]\(CH_3CH_2OH\)[/tex].
Among the given options:
- [tex]\(CH_3CH_2OH\)[/tex]
- [tex]\(CH_3CH_2CH_2OH\)[/tex]
- [tex]\(CH_3CH_2CH_2CH_2OH\)[/tex]
- [tex]\(CH_3CH_2CH_2COOH\)[/tex]
The correct alcohol formed is [tex]\(CH_3CH_2OH\)[/tex].
So, the answer is:
[tex]\[ \boxed{CH_3CH_2OH} \][/tex]
