Answer :
Let's address the problem step-by-step.
### Unknown Quantities
There are two unknown quantities in this case—the width and the length of the rectangle.
- Call the width of the pen [tex]\( a \)[/tex].
### Expression for the Length
The problem states that the length of the rectangle is twice as long as the width.
- Therefore, the expression for the length is [tex]\( 2a \)[/tex].
### Formula for the Perimeter of a Rectangle
The formula for the perimeter of a rectangle is given by:
[tex]\[ \text{perimeter of rectangle} = 2 \times (\text{length} + \text{width}) \][/tex]
- Substitute the expressions for the length and width into the formula:
[tex]\[ \begin{aligned} \text{perimeter of rectangle} &= 2 \times (\text{length} + \text{width}) \\ &= 2 \times (2a + a) \\ &= 2 \times (3a) \\ &= 6a \end{aligned} \][/tex]
So, the expression for the perimeter of Andrew's holding pen is [tex]\( 6a \)[/tex].
### Unknown Quantities
There are two unknown quantities in this case—the width and the length of the rectangle.
- Call the width of the pen [tex]\( a \)[/tex].
### Expression for the Length
The problem states that the length of the rectangle is twice as long as the width.
- Therefore, the expression for the length is [tex]\( 2a \)[/tex].
### Formula for the Perimeter of a Rectangle
The formula for the perimeter of a rectangle is given by:
[tex]\[ \text{perimeter of rectangle} = 2 \times (\text{length} + \text{width}) \][/tex]
- Substitute the expressions for the length and width into the formula:
[tex]\[ \begin{aligned} \text{perimeter of rectangle} &= 2 \times (\text{length} + \text{width}) \\ &= 2 \times (2a + a) \\ &= 2 \times (3a) \\ &= 6a \end{aligned} \][/tex]
So, the expression for the perimeter of Andrew's holding pen is [tex]\( 6a \)[/tex].