Indicate the equation of the given line in standard form.

Consider a square with vertices at [tex]\( A(-3, 3) \)[/tex], [tex]\( B(3, 3) \)[/tex], [tex]\( C(3, -3) \)[/tex], and [tex]\( D(-3, -3) \)[/tex].

What is the equation of the diagonal line [tex]\( BD \)[/tex]?

Write your answer in the box below.



Answer :

To determine the equation of the diagonal line [tex]\(BC\)[/tex] of the square, we need to follow these steps:

1. Identify the coordinates of points B and C:
- [tex]\(B(3, 3)\)[/tex]
- [tex]\(C(3, -3)\)[/tex]

2. Calculate the slope of line BC:
The slope [tex]\(m\)[/tex] between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is given by:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Substituting the coordinates of B and C:
[tex]\[ m = \frac{-3 - 3}{3 - 3} \][/tex]
However, notice that the x-coordinates of B and C are the same ([tex]\(3\)[/tex]). This indicates that the line BC is vertical.

3. Equation of a vertical line:
For any vertical line, the equation is simply [tex]\(x = k\)[/tex], where [tex]\(k\)[/tex] is the constant x-coordinate value of any point on the line.

Since both points B and C have an x-coordinate of [tex]\(3\)[/tex], the equation of the line BC in standard form is:
[tex]\[ x = 3 \][/tex]

Therefore, the equation of the diagonal line BC in standard form is:
[tex]\[ x = 3 \][/tex]