### Tuition Costs

In 1990, the cost of tuition at a large Midwestern university was [tex]$\$[/tex]92[tex]$ per credit hour. In 2003, tuition had risen to $[/tex]\[tex]$287$[/tex] per credit hour.

1. Determine a linear function [tex]$C(x)$[/tex] to represent the cost of tuition as a function of [tex]$x$[/tex], the number of years since 1990.
[tex]\[
C(x) = \square
\][/tex]

2. In the year 2010, tuition will be [tex]$\$[/tex] \square[tex]$ per credit hour.

3. In the year $[/tex]\square[tex]$, tuition will be $[/tex]\[tex]$527$[/tex] per credit hour.



Answer :

To approach this problem, we start by understanding that we need to establish a linear relationship between the cost of tuition and the number of years since 1990. We'll identify the linear function [tex]\(C(x)\)[/tex] where [tex]\(x\)[/tex] is the number of years since 1990.

### Step-by-Step Solution:

1. Identify Given Information:
- Tuition in 1990, [tex]\(C(0)\)[/tex]: \[tex]$92 - Tuition in 2003, \(C(13)\): \$[/tex]287

Here, [tex]\(13\)[/tex] represents the number of years from 1990 to 2003.

2. Calculate the Slope (Rate of Change):

The slope [tex]\(m\)[/tex] of the linear function can be calculated as the rate of change in tuition costs per year. This is done using the formula for the slope between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex]:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Substituting the given values:
[tex]\[ m = \frac{287 - 92}{13 - 0} = \frac{195}{13} = 15 \][/tex]

Thus, the slope [tex]\(m\)[/tex] is 15.

3. Establish the Linear Function:

The general form of a linear function is:
[tex]\[ C(x) = mx + b \][/tex]
Where [tex]\(m\)[/tex] is the slope, and [tex]\(b\)[/tex] is the y-intercept (initial value when [tex]\(x = 0\)[/tex]).

Given that the tuition in 1990 ([tex]\(x = 0\)[/tex]) was \[tex]$92, \(b = 92\). Thus, the linear function \(C(x)\) is: \[ C(x) = 15x + 92 \] 4. Calculate Tuition in 2010: For the year 2010, \(x\) is the number of years since 1990: \[ x = 2010 - 1990 = 20 \] Substituting \(x = 20\) into the linear function: \[ C(20) = 15 \cdot 20 + 92 = 300 + 92 = 392 \] Therefore, the tuition in 2010 will be \$[/tex]392 per credit hour.

5. Determine the Year When Tuition Will Be \[tex]$527: We need to find the year \(x\) when \(C(x) = 527\): \[ 527 = 15x + 92 \] Solving for \(x\): \[ 527 - 92 = 15x \] \[ 435 = 15x \] \[ x = \frac{435}{15} = 29 \] The number of years since 1990 when the tuition will be \$[/tex]527 is 29 years. Adding this to 1990 gives:
[tex]\[ 1990 + 29 = 2019 \][/tex]

Hence, the year when tuition will be \[tex]$527 per credit hour is 2019. ### Final Answers: - The linear function \(C(x) = 15x + 92\) - In the year 2010, tuition will be \$[/tex]392 per credit hour.
- In the year 2019, tuition will be \$527 per credit hour.