Answer the question based on the data in the table.

\begin{tabular}{|c|c|c|c|}
\hline
\multirow{2}{*}{\begin{tabular}{c}
Shirt \\
Color
\end{tabular}} & \multicolumn{3}{|c|}{ Size } \\
\cline { 2 - 4 }
& Large & Medium & Total \\
\hline
Red & 42 & 48 & 90 \\
\hline
Blue & 35 & 40 & 75 \\
\hline
Total & 77 & 88 & 165 \\
\hline
\end{tabular}

If you pick a shirt at random from the given batch of 165 shirts, what is the probability that it is red and the size is medium?

A. [tex]$\frac{88}{165}$[/tex]

B. [tex]$\frac{90}{105}$[/tex]

C. [tex]$\frac{48}{105}$[/tex]

D. [tex]$\frac{90}{2725}$[/tex]

E. [tex]$\frac{48}{27225}$[/tex]



Answer :

To determine the probability that a randomly selected shirt from the batch is red and medium-sized, we follow these steps:

1. Identify the total number of shirts: The total number of shirts is 165 (as provided in the last column of the table).

2. Identify the number of red, medium-sized shirts: From the table, the number of red, medium-sized shirts is given as 48.

3. Calculate the probability: The probability of picking a red and medium-sized shirt is the ratio of the number of red, medium-sized shirts to the total number of shirts.

So the calculation is:
[tex]\[ \text{Probability} = \frac{\text{Number of red, medium-sized shirts}}{\text{Total number of shirts}} = \frac{48}{165} \][/tex]

Therefore, the correct answer is:
[tex]\[ \boxed{\frac{48}{165}} \][/tex]

Upon simplifying the options given:
- None of the options match exactly.
- The proper fraction representation of our ratio [tex]\(\frac{48}{165}\)[/tex] does not match with any of the options. Revisiting the problem's instructions and options, answer [tex]\( \boxed{E} \)[/tex] is the closest.

The computed probability in decimal form from calculations is [tex]\(0.2909090909090909\)[/tex], confirming the fraction here stands accurate. The fraction representing probability simplified may find incorrect simplifications listed among options.

Summarizing, original calculations stand, answer = option [tex]\( \frac{48}{165} \)[/tex].