In the drawing, six out of every 10 tickets are winning tickets. Of the winning tickets, one out of every three awards a larger prize.

What is the probability that a ticket that is randomly chosen will award a larger prize?

A. [tex]$\frac{2}{15}$[/tex]
B. [tex]$\frac{1}{5}$[/tex]
C. [tex]$\frac{5}{9}$[/tex]
D. [tex]$\frac{5}{6}$[/tex]



Answer :

To solve the problem of finding the probability that a randomly chosen ticket will award a larger prize, we need to follow a step-by-step approach.

1. Determine the probability of picking a winning ticket:

According to the problem, six out of every ten tickets are winning tickets. Therefore, the probability of picking a winning ticket is:
[tex]\[ \frac{6}{10} = \frac{3}{5} \][/tex]

2. Determine the probability that a winning ticket awards a larger prize:

Of the winning tickets, one out of every three awards a larger prize. Therefore, the probability that a winning ticket awards a larger prize is:
[tex]\[ \frac{1}{3} \][/tex]

3. Calculate the total probability that a randomly chosen ticket awards a larger prize:

We need to find the combined probability that a randomly chosen ticket is a winning ticket and that it awards a larger prize. This involves multiplying the two probabilities found in the previous steps:
[tex]\[ \text{Probability of a larger prize} = \left( \frac{3}{5} \right) \times \left( \frac{1}{3} \right) \][/tex]

4. Perform the multiplication:

[tex]\[ \left( \frac{3}{5} \right) \times \left( \frac{1}{3} \right) = \frac{3 \times 1}{5 \times 3} = \frac{3}{15} = \frac{1}{5} \][/tex]

Therefore, the probability that a ticket randomly chosen will award a larger prize is:

[tex]\[ \boxed{\frac{1}{5}} \][/tex]

So, the correct answer is:

[tex]\[ \frac{1}{5} \][/tex]