Certainly! Let's solve each of these step-by-step:
1. Fill in the blank:
Given: [tex]\(4598 + 2341 = 2341 + \, \underline{\hspace{1cm}} \)[/tex]
According to the commutative property of addition, the order in which two numbers are added does not change the sum. Therefore:
[tex]\[
\underline{4598}
\][/tex]
So, [tex]\(4598 + 2341 = 2341 + 4598\)[/tex].
2. Fill in the blank:
Given: [tex]\(5273 + 6250 = \, \underline{\hspace{2cm}} \)[/tex]
Add the numbers together:
[tex]\[
5273 + 6250 = 11523
\][/tex]
So, [tex]\(5273 + 6250 = \underline{11523}\)[/tex].
3. Fill in the blank:
Given: [tex]\(2256 - 0 = \, \underline{\hspace{2cm}} \)[/tex]
Subtracting zero from any number leaves the number unchanged:
[tex]\[
2256 - 0 = 2256
\][/tex]
So, [tex]\(2256 - 0 = \underline{2256}\)[/tex].
4. Fill in the blank:
Given: [tex]\(1251 - \, \underline{\hspace{2cm}} = 0\)[/tex]
Subtracting a number from itself results in zero:
[tex]\[
1251 - 1251 = 0
\][/tex]
So, [tex]\(1251 - \underline{1251} = 0\)[/tex].
5. Fill in the blank:
Given: [tex]\(34 \times 10 = \, \underline{\hspace{2cm}} \)[/tex]
Multiplying 34 by 10:
[tex]\[
34 \times 10 = 340
\][/tex]
So, [tex]\(34 \times 10 = \underline{340}\)[/tex].
6. Fill in the blank:
Given: [tex]\(56 \times 100 = \, \underline{\hspace{2cm}} \)[/tex]
Multiplying 56 by 100:
[tex]\[
56 \times 100 = 5600
\][/tex]
So, [tex]\(56 \times 100 = \underline{5600}\)[/tex].
The final filled-in blanks are:
1. [tex]\(4598 + 2341 = 2341 + \underline{4598}\)[/tex]
2. [tex]\(5273 + 6250 = \underline{11523}\)[/tex]
3. [tex]\(2256 - 0 = \underline{2256}\)[/tex]
4. [tex]\(1251 - \underline{1251} = 0\)[/tex]
5. [tex]\(34 \times 10 = \underline{340}\)[/tex]
6. [tex]\(56 \times 100 = \underline{5600}\)[/tex]
