A wall with an area of [tex]4 \, \text{m}^2[/tex] was painted yellow and brown. The area of the wall painted yellow was 3 times as large as the area painted brown.

a. What was the ratio of the area painted yellow to the area painted brown?
b. What fraction of the total area of the wall was painted brown?
c. Find the area of the wall painted yellow.



Answer :

Let's solve the problem step-by-step.

First, define the variables:
- Let the area painted brown be [tex]\( x \)[/tex] square meters.
- The area painted yellow is 3 times the area painted brown, which can be expressed as [tex]\( 3x \)[/tex] square meters.
- The total area of the wall is 4 square meters.

### Step 1: Formulate the equation for the total area

The total area of the wall is the sum of the areas painted brown and yellow:
[tex]\[ x + 3x = 4 \][/tex]

Combine like terms:
[tex]\[ 4x = 4 \][/tex]

Solve for [tex]\( x \)[/tex]:
[tex]\[ x = 1 \][/tex]

### Step 2: Determine the areas painted brown and yellow

Since [tex]\( x = 1 \)[/tex], the area painted brown is:
[tex]\[ 1 \text{ square meter} \][/tex]

The area painted yellow is:
[tex]\[ 3x = 3 \times 1 = 3 \text{ square meters} \][/tex]

### Step 3: Answer each specific question

#### (a) What was the ratio of the area painted yellow to the area painted brown?

The ratio of the area painted yellow to the area painted brown is:
[tex]\[ \frac{\text{yellow}}{\text{brown}} = \frac{3}{1} = 3 \][/tex]

#### (b) What fraction of the total area of the wall was painted brown?

The fraction of the total area painted brown is:
[tex]\[ \frac{\text{area painted brown}}{\text{total area}} = \frac{1}{4} \][/tex]

#### (c) Find the area of the wall painted yellow

The area of the wall painted yellow is:
[tex]\[ 3 \text{ square meters} \][/tex]

### Summary

- The ratio of the area painted yellow to the area painted brown is 3.
- The fraction of the total area of the wall that was painted brown is [tex]\( \frac{1}{4} \)[/tex].
- The area of the wall painted yellow is 3 square meters.