To solve the problem of finding the number in the grid that, when divided by 8, leaves a remainder of 1, let's carefully examine each number and perform the division operation.
Here is the grid for reference:
[tex]\[
\begin{tabular}{|l|l|l|}
\hline 67 & 72 & 51 \\
\hline 42 & 73 & 64 \\
\hline 60 & 20 & 69 \\
\hline
\end{tabular}
\][/tex]
1. 67 divided by 8:
[tex]\[
67 \div 8 = 8 \text{ remainder } 3 \quad \text{so}\quad 67 \mod 8 = 3
\][/tex]
This does not meet our requirement as the remainder is 3.
2. 72 divided by 8:
[tex]\[
72 \div 8 = 9 \text{ remainder } 0 \quad \text{so}\quad 72 \mod 8 = 0
\][/tex]
This does not meet our requirement as the remainder is 0.
3. 51 divided by 8:
[tex]\[
51 \div 8 = 6 \text{ remainder } 3 \quad \text{so}\quad 51 \mod 8 = 3
\][/tex]
This does not meet our requirement as the remainder is 3.
4. 42 divided by 8:
[tex]\[
42 \div 8 = 5 \text{ remainder } 2 \quad \text{so}\quad 42 \mod 8 = 2
\][/tex]
This does not meet our requirement as the remainder is 2.
5. 73 divided by 8:
[tex]\[
73 \div 8 = 9 \text{ remainder } 1 \quad \text{so}\quad 73 \mod 8 = 1
\][/tex]
This meets our requirement as the remainder is 1.
6. 64 divided by 8:
[tex]\[
64 \div 8 = 8 \text{ remainder } 0 \quad \text{so}\quad 64 \mod 8 = 0
\][/tex]
This does not meet our requirement as the remainder is 0.
7. 60 divided by 8:
[tex]\[
60 \div 8 = 7 \text{ remainder } 4 \quad \text{so}\quad 60 \mod 8 = 4
\][/tex]
This does not meet our requirement as the remainder is 4.
8. 20 divided by 8:
[tex]\[
20 \div 8 = 2 \text{ remainder } 4 \quad \text{so}\quad 20 \mod 8 = 4
\][/tex]
This does not meet our requirement as the remainder is 4.
9. 69 divided by 8:
[tex]\[
69 \div 8 = 8 \text{ remainder } 5 \quad \text{so}\quad 69 \mod 8 = 5
\][/tex]
This does not meet our requirement as the remainder is 5.
After examining all the numbers in the grid, the number that, when divided by 8, leaves a remainder of 1 is 73.
