Copy and complete the table of values for [tex]\( y = x^2 + 7 \)[/tex].
What numbers replace A and B?

[tex]\[
\begin{array}{c||c|c|c|c|c}
x & -2 & -1 & 0 & 1 & 2 \\
\hline
y & A & 8 & 7 & 8 & B \\
\end{array}
\][/tex]



Answer :

To complete the table of values for the function [tex]\( y = x^2 + 7 \)[/tex], we need to calculate the values of [tex]\( y \)[/tex] for given [tex]\( x \)[/tex] values.

The general form of the function [tex]\( y = x^2 + 7 \)[/tex] is:

1. For [tex]\( x = -2 \)[/tex]:
[tex]\[ y = (-2)^2 + 7 = 4 + 7 = 11 \][/tex]
Hence, [tex]\( A = 11 \)[/tex].

2. For [tex]\( x = -1 \)[/tex]:
[tex]\[ y = (-1)^2 + 7 = 1 + 7 = 8 \][/tex]
As given, [tex]\( y = 8 \)[/tex] for [tex]\( x = -1 \)[/tex].

3. For [tex]\( x = 0 \)[/tex]:
[tex]\[ y = 0^2 + 7 = 0 + 7 = 7 \][/tex]
As given, [tex]\( y = 7 \)[/tex] for [tex]\( x = 0 \)[/tex].

4. For [tex]\( x = 1 \)[/tex]:
[tex]\[ y = 1^2 + 7 = 1 + 7 = 8 \][/tex]
As given, [tex]\( y = 8 \)[/tex] for [tex]\( x = 1 \)[/tex].

5. For [tex]\( x = 2 \)[/tex]:
[tex]\[ y = 2^2 + 7 = 4 + 7 = 11 \][/tex]
Hence, [tex]\( B = 11 \)[/tex].

Putting these values into the table, we get:

[tex]\[ \begin{tabular}{c||c|c|c|c|c} $x$ & -2 & -1 & 0 & 1 & 2 \\ \hline $y$ & 11 & 8 & 7 & 8 & 11 \\ \end{tabular} \][/tex]

Therefore, the numbers that replace [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are [tex]\( 11 \)[/tex] and [tex]\( 11 \)[/tex] respectively.