What is the weight (in grams) of a liquid that exactly fills a 465-milliliter container if the density of the liquid is [tex]$0.982 \frac{\text{grams}}{\text{milliliter}}$[/tex]?

Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.

Answer for Blank 1:



Answer :

To solve the problem of finding the weight of a liquid based on its volume and density, follow these steps:

1. Understand the given values:
- The volume of the liquid is 465 milliliters.
- The density of the liquid is [tex]\(0.982 \frac{\text {grams}}{\text {milliliter}}\)[/tex].

2. Use the formula for weight:
- The weight of a liquid can be found using the formula:
[tex]\[ \text{Weight (grams)} = \text{Volume (milliliters)} \times \text{Density (grams per milliliter)} \][/tex]

3. Plug in the given values:
- Volume = 465 milliliters
- Density = [tex]\(0.982 \frac{\text {grams}}{\text {milliliter}}\)[/tex]

4. Perform the multiplication:
- Calculate the weight:
[tex]\[ \text{Weight} = 465 \times 0.982 \][/tex]

5. Calculate the product:
- [tex]\[ 465 \times 0.982 = 456.63 \][/tex]

6. Round to the nearest hundredth if necessary:
- In this case, the product is already to the nearest hundredth (456.63).

Therefore, the weight of the liquid is 456.63 grams.

Answer for Blank 1: 456.63