Explain this because I’m getting it wrong every time, my teacher is getting annoyed that I don’t know how to do it.
A 901 kg car accelerates from rest to a speed of 37 m/s in 7.6 s. Determine the net force on the car.

According to Newton's second law of motion, the net force (∑F) on the car is equal to its mass (m) times its acceleration (a). The acceleration is equal to the change in velocity (Δv) over time (Δt).

[tex]\Large \text {$ \Sigma F=ma $}\\\\\Large \text {$ \Sigma F=m $} \huge \text {$ \frac{\Delta v}{\Delta t} $}\\\\\Large \text {$ \Sigma F=(901\ kg) $} \huge \text {$ \frac{37\ m/s-0\ m/s}{7.6\ s} $}\\\\\Large \text {$ \Sigma F \approx 4400\ N $}[/tex]

Rounded to two significant figures, the net force on the car is approximately 4400 Newtons.

Explain this because I’m getting it wrong every time, my teacher is getting annoyed that I don’t know how to do it. A 901 kg car accelerates from rest to a speed of 37 m/s in 7.6 s. Determine the net force on the car.

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Explain this because I’m getting it wrong every time, my teacher is getting annoyed that I don’t know how to do it.
A 901 kg car accelerates from rest to a speed of 37 m/s in 7.6 s. Determine the net force on the car.