To solve this problem, we need to match each given probability to the corresponding scenario described.
### Step-by-Step Solution:
1. Scenario: The probability that both numbers are less than 7 if the same number can be chosen twice.
- This probability is given as [tex]\(\frac{4}{9}\)[/tex].
2. Scenario: The probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice.
- This probability is given as [tex]\(\frac{1}{6}\)[/tex].
3. Scenario: The probability that both numbers are greater than 6 if the same number can be chosen twice.
- This probability is given as [tex]\(\frac{1}{12}\)[/tex].
4. Scenario: The probability that both numbers are even numbers if the same numbers cannot be chosen twice.
- This probability is given as [tex]\(\frac{1}{9}\)[/tex].
### Assigning Probabilities to Scenarios:
1. The probability that both numbers are less than 7 if the same number can be chosen twice is [tex]\(\frac{4}{9}\)[/tex].
2. The probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice is [tex]\(\frac{1}{6}\)[/tex].
3. The probability that both numbers are greater than 6 if the same number can be chosen twice is [tex]\(\frac{1}{12}\)[/tex].
4. The probability that both numbers are even numbers if the same numbers cannot be chosen twice is [tex]\(\frac{1}{9}\)[/tex].
Thus, the correct matching is:
- [tex]\(\frac{4}{9}\)[/tex]: The probability that both numbers are less than 7 if the same number can be chosen twice.
- [tex]\(\frac{1}{6}\)[/tex]: The probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice.
- [tex]\(\frac{1}{12}\)[/tex]: The probability that both numbers are greater than 6 if the same number can be chosen twice.
- [tex]\(\frac{1}{9}\)[/tex]: The probability that both numbers are even numbers if the same numbers cannot be chosen twice.
