To solve the problems given, let’s analyze each situation step-by-step.
First Mating: Heterozygous male (genotype: [tex]\( Ww \)[/tex]) with homozygous recessive female (genotype: [tex]\( ww \)[/tex])
We use a Punnett square to determine the genotype probabilities of the offspring:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
By analyzing the Punnett square:
- We have 2 squares with genotype [tex]\( Ww \)[/tex] (heterozygous).
- We have 2 squares with genotype [tex]\( ww \)[/tex] (homozygous recessive).
There are 4 possible outcomes in total, so the probability of the offspring being heterozygous ([tex]\( Ww \)[/tex]) is:
[tex]\[
\frac{2}{4} = 0.5
\][/tex]
So the first drop-down menu should state:
"50%".
Second Mating: Heterozygous ([tex]\( Ww \)[/tex]) crossed with Homozygous dominant ([tex]\( WW \)[/tex])
We use another Punnett square to determine the genotype probabilities:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\][/tex]
By analyzing this Punnett square:
- We have 2 squares with genotype [tex]\( WW \)[/tex] (homozygous dominant).
- We have 2 squares with genotype [tex]\( Ww \)[/tex] (heterozygous).
There are 4 possible outcomes in total, and none of these result in a homozygous recessive ([tex]\( ww \)[/tex]) genotype.
Hence, the probability of having a homozygous recessive offspring is:
[tex]\[
0
\][/tex]
So the second drop-down menu should state:
"0%".
