Answer :
To determine whose results are more reliable, we need to calculate the range of the distances diffused for both students. The range is the difference between the maximum and minimum values in the data set. A narrower range indicates more consistent results.
### Step-by-Step Solution:
1. Identify the data for each student:
- Student 1: 3.25 mm, 3.17 mm, 3.26 mm, 3.64 mm, 3.44 mm
- Student 2: 3.14 mm, 3.43 mm, 3.22 mm, 3.37 mm, 3.28 mm
2. Calculate the range for Student 1:
- Find the maximum value for Student 1: [tex]\( \max(3.25, 3.17, 3.26, 3.64, 3.44) = 3.64 \)[/tex]
- Find the minimum value for Student 1: [tex]\( \min(3.25, 3.17, 3.26, 3.64, 3.44) = 3.17 \)[/tex]
- Calculate the range: [tex]\( \text{Range}_{\text{Student 1}} = 3.64 - 3.17 = 0.470 \)[/tex]
3. Calculate the range for Student 2:
- Find the maximum value for Student 2: [tex]\( \max(3.14, 3.43, 3.22, 3.37, 3.28) = 3.43 \)[/tex]
- Find the minimum value for Student 2: [tex]\( \min(3.14, 3.43, 3.22, 3.37, 3.28) = 3.14 \)[/tex]
- Calculate the range: [tex]\( \text{Range}_{\text{Student 2}} = 3.43 - 3.14 = 0.290 \)[/tex]
4. Compare the ranges:
- Student 1's range: 0.470 mm
- Student 2's range: 0.290 mm
5. Determine which range is narrower:
- Student 2 has a narrower range of 0.290 mm compared to Student 1's range of 0.470 mm.
### Conclusion:
Since a narrower range indicates more consistent results, Student 2's results are more reliable.
Thus, the correct answer is A. Student 2, because they have a narrower range.
### Step-by-Step Solution:
1. Identify the data for each student:
- Student 1: 3.25 mm, 3.17 mm, 3.26 mm, 3.64 mm, 3.44 mm
- Student 2: 3.14 mm, 3.43 mm, 3.22 mm, 3.37 mm, 3.28 mm
2. Calculate the range for Student 1:
- Find the maximum value for Student 1: [tex]\( \max(3.25, 3.17, 3.26, 3.64, 3.44) = 3.64 \)[/tex]
- Find the minimum value for Student 1: [tex]\( \min(3.25, 3.17, 3.26, 3.64, 3.44) = 3.17 \)[/tex]
- Calculate the range: [tex]\( \text{Range}_{\text{Student 1}} = 3.64 - 3.17 = 0.470 \)[/tex]
3. Calculate the range for Student 2:
- Find the maximum value for Student 2: [tex]\( \max(3.14, 3.43, 3.22, 3.37, 3.28) = 3.43 \)[/tex]
- Find the minimum value for Student 2: [tex]\( \min(3.14, 3.43, 3.22, 3.37, 3.28) = 3.14 \)[/tex]
- Calculate the range: [tex]\( \text{Range}_{\text{Student 2}} = 3.43 - 3.14 = 0.290 \)[/tex]
4. Compare the ranges:
- Student 1's range: 0.470 mm
- Student 2's range: 0.290 mm
5. Determine which range is narrower:
- Student 2 has a narrower range of 0.290 mm compared to Student 1's range of 0.470 mm.
### Conclusion:
Since a narrower range indicates more consistent results, Student 2's results are more reliable.
Thus, the correct answer is A. Student 2, because they have a narrower range.