The function [tex]$C(t) = C_0(1 + r)^t$[/tex] models the rise in the cost of a product that has a cost of [tex]$C_0$[/tex] today, subject to an average yearly inflation rate of [tex][tex]$r$[/tex][/tex] for [tex]$t$[/tex] years. If the average annual rate of inflation over the next 5 years is assumed to be [tex]$3.5\%$[/tex], what will the inflation-adjusted cost of a [tex][tex]$\$[/tex]210,000$[/tex] boat be in 5 years? Round to two decimal places.

Answer:



Answer :

To determine the inflation-adjusted cost of a boat that has an initial cost of \[tex]$210,000 today, given an average annual inflation rate of 3.5% over the next 5 years, we will use the function: \[ C(t) = C_0 (1 + r)^t \] where: - \( C(t) \) is the cost of the boat after \( t \) years, - \( C_0 \) is the initial cost of the boat (today's cost), - \( r \) is the average annual inflation rate, - \( t \) is the number of years. Step-by-Step Solution: 1. Identify the given values: - Initial cost, \( C_0 \) = \$[/tex]210,000
- Annual inflation rate, [tex]\( r \)[/tex] = 3.5% = 0.035 (as a decimal)
- Number of years, [tex]\( t \)[/tex] = 5

2. Substitute the given values into the formula:

[tex]\[ C(t) = 210,000 \times (1 + 0.035)^5 \][/tex]
[tex]\[ C(t) = 210,000 \times (1.035)^5 \][/tex]

3. Calculate [tex]\( (1.035)^5 \)[/tex]:

[tex]\[ (1.035)^5 \approx 1.1877 \][/tex]

4. Multiply the initial cost [tex]\( C_0 \)[/tex] by the result from the previous step:

[tex]\[ C(t) = 210,000 \times 1.1877 \][/tex]
[tex]\[ C(t) \approx 249,414.12418584366 \][/tex]

5. Round the result to two decimal places:

[tex]\[ C(t) \approx 249,414.12 \][/tex]

So, the inflation-adjusted cost of the \[tex]$210,000 boat in 5 years, with an annual inflation rate of 3.5%, will be approximately \$[/tex]249,414.12.