A charter flight charges a fare of [tex]$\$[/tex]300[tex]$ per person plus $[/tex]\[tex]$30$[/tex] per person for each unsold seat on the plane. The plane holds 100 passengers. Let [tex]$x$[/tex] represent the number of unsold seats. Complete parts (a) through (d).

(a) Find an expression for the total revenue received for the flight [tex]$R(x)$[/tex]. (Hint: Multiply the number of people flying, [tex]$100 - x$[/tex], by the price per ticket.)

[tex]$
R(x) =
$[/tex]

[tex]$\square$[/tex]



Answer :

Certainly! Let's break this down step by step:

1. Identify the Variables:
- Let [tex]\( x \)[/tex] be the number of unsold seats.
- The plane holds 100 passengers.

2. Number of People Flying:
Since [tex]\( x \)[/tex] accounts for the unsold seats, the number of people flying is:
[tex]\[ \text{Number of people flying} = 100 - x \][/tex]

3. Price per Ticket:
The fare per person is [tex]$\$[/tex]300[tex]$, and an additional $[/tex]\[tex]$30$[/tex] is charged for each unsold seat. Therefore, the price per ticket is:
[tex]\[ \text{Price per ticket} = 300 + 30x \][/tex]

4. Total Revenue Expression:
The total revenue [tex]\( R(x) \)[/tex] is the number of people flying multiplied by the price per ticket. Therefore, we multiply the expressions from steps 2 and 3:
[tex]\[ R(x) = (100 - x) \times (300 + 30x) \][/tex]

Therefore, the expression for the total revenue received for the flight, [tex]\( R(x) \)[/tex], is:
[tex]\[ R(x) = (100 - x) \times (300 + 30x) \][/tex]