Answered

Solve the following:

[tex]\[ 11 \times 2 \frac{7}{11} \][/tex]

Select one of the four options:

[tex]\[
\begin{array}{lr}
A. \ 33 & B. \ 29 \\
C. \ 31 & D. \ 35
\end{array}
\][/tex]



Answer :

Certainly! Let's solve the given problem step by step.

We need to calculate the product of a whole number and a mixed number:

[tex]\[ 11 \times 2 \frac{7}{11} \][/tex]

First, let's convert the mixed number [tex]\(2 \frac{7}{11}\)[/tex] into an improper fraction. A mixed number has the form [tex]\( \text{whole part} + \frac{\text{numerator}}{\text{denominator}}\)[/tex]. So:

[tex]\[ 2 \frac{7}{11} = 2 + \frac{7}{11} \][/tex]

To add these, we need a common denominator. The simplest way is to convert the whole number 2 into a fraction with the same denominator:

[tex]\[ 2 = \frac{2 \times 11}{11} = \frac{22}{11} \][/tex]

Now, add this fraction to [tex]\(\frac{7}{11}\)[/tex]:

[tex]\[ \frac{22}{11} + \frac{7}{11} = \frac{22 + 7}{11} = \frac{29}{11} \][/tex]

With this, the mixed number [tex]\(2 \frac{7}{11}\)[/tex] becomes the improper fraction [tex]\(\frac{29}{11}\)[/tex].

Next, we multiply the whole number 11 by this improper fraction:

[tex]\[ 11 \times \frac{29}{11} \][/tex]

When multiplying by a fraction, if the denominator of the fraction and the whole number are the same, they cancel out:

[tex]\[ 11 \times \frac{29}{11} = 29 \][/tex]

Therefore, the product is 29.

Finally, we need to select the closest value to 29 from the given choices:

[tex]\[ \begin{array}{lr} 33 & 29 \\ 31 & 35 \end{array} \][/tex]

Clearly, the closest value is 29.

To summarize, the product of [tex]\(11 \times 2 \frac{7}{11}\)[/tex] is 29, and among the choices provided, the correct answer is:

[tex]\[ \boxed{29} \][/tex]