Certainly! Let's go through the problem step-by-step to identify the correct nuclide symbol.
1. Understanding the Mass Number and Neutrons:
- The mass number (A) of the nuclide is given as 60.
- The number of neutrons (n) in this nuclide is given as 33.
2. Relating Mass Number to Protons and Neutrons:
- The mass number (A) is the sum of the number of protons (p) and the number of neutrons (n):
[tex]\[
A = p + n
\][/tex]
- We are given:
[tex]\[
60 = p + 33
\][/tex]
3. Solving for the Number of Protons:
- To find the number of protons, rearrange the equation:
[tex]\[
p = 60 - 33
\][/tex]
- Calculate:
[tex]\[
p = 27
\][/tex]
4. Identifying the Element:
- The Atomic Number (Z), which is the number of protons, is 27.
- The element with the atomic number 27 is Cobalt (Co).
5. Writing the Nuclide Symbol:
- Based on the mass number (A = 60) and the atomic number (Z = 27), the nuclide symbol is written as:
[tex]\[
{}_{27}^{60} Co
\][/tex]
6. Comparing with Given Options:
- Let's match the options with our result:
[tex]\[
{}_{60}^{27} Co \quad (\text{match: } {}_{27}^{60} Co): \text{ matches when written correctly, hence correct}
\][/tex]
[tex]\[
{}_{50}^{30} CO \quad (\text{wrong mass number})
\][/tex]
[tex]\[
{}_{33}^{80} CO \quad (\text{wrong configuration})
\][/tex]
[tex]\[
{}_{27} CO \quad (\text{wrong mass number})
\][/tex]
Among the given options, the correct symbol for the nuclide is:
[tex]\[
{}_{60}^{27} Co
\][/tex]
Therefore, the correct answer is:
[tex]\[
\boxed{{}_{60}^{27} Co}
\][/tex]
