Answered

Leo had [tex]\$91[/tex], which is 7 times as much money as Alison had. How much money did Alison have?

Select the correct solution method below, where [tex]x[/tex] represents Alison's money:

A. [tex]x - 7 = 91[/tex]. Add 7 to both sides. Alison had [tex]\$98[/tex].
B. [tex]\frac{x}{7} = 91[/tex]. Multiply both sides by 7. Alison had [tex]\$637[/tex].
C. [tex]7x = 91[/tex]. Divide both sides by 7. Alison had [tex]\$13[/tex].
D. [tex]x + 7 = 91[/tex]. Subtract 7 from both sides. Alison had [tex]\$84[/tex].



Answer :

To find out how much money Alison had, we are given that Leo had [tex]$91, which is 7 times as much money as Alison had. We denote the amount of money Alison had by \( x \). The relationship between Leo's money and Alison's money can be written as: \[ 7x = 91 \] We need to solve for \( x \). To do this, we need to isolate \( x \) on one side of the equation. We can do this by dividing both sides of the equation by 7: \[ x = \frac{91}{7} \] Performing the division yields: \[ x = 13 \] Therefore, Alison had $[/tex]13.

Among the given solution methods, the correct one is:
C. [tex]\( 7x = 91 \)[/tex]. Divide both sides by 7. Alison had $13.