To determine the power produced by a flashlight with a given voltage and current, we can use the formula:
[tex]\[ P = V \times I \][/tex]
where [tex]\( P \)[/tex] is the power in watts, [tex]\( V \)[/tex] is the voltage in volts, and [tex]\( I \)[/tex] is the current in amperes.
Given:
[tex]\[ V = 12 \, \text{volts} \][/tex]
[tex]\[ I = 6.5 \times 10^{-2} \, \text{amp} \][/tex]
Substitute these values into the formula:
[tex]\[ P = 12 \, \text{volts} \times 6.5 \times 10^{-2} \, \text{amp} \][/tex]
Upon solving this, we find:
[tex]\[ P = 0.78 \, \text{watts} \][/tex]
Therefore, the correct answer is:
D. 0.78 watts
