Gas Laws Fact Sheet

\begin{tabular}{|l|l|}
\hline
Ideal gas law & [tex]$PV = nRT$[/tex] \\
\hline
& [tex]$R = 8.314 \frac{L \cdot kPa}{mol \cdot K}$[/tex] \\
Ideal gas constant & or \\
& [tex]$R = 0.0821 \frac{L \cdot atm}{mol \cdot K}$[/tex] \\
\hline
Standard atmospheric pressure & [tex]$1 \, atm = 101.3 \, kPa$[/tex] \\
\hline
Celsius to Kelvin conversion & [tex]$K = ^{\circ}C + 273.15$[/tex] \\
\hline
\end{tabular}

Select the correct answer.

The gas in a sealed container has an absolute pressure of 125.4 kilopascals. If the air around the container is at a pressure of 99.8 kilopascals, what is the gauge pressure inside the container?

A. 1.5 kPa
B. 24.1 kPa
C. 25.6 kPa
D. 112.6 kPa



Answer :

To find the gauge pressure inside the container, we need to understand the relationship between absolute pressure, atmospheric pressure, and gauge pressure.

Absolute Pressure: This is the total pressure exerted by the gas, including the atmospheric pressure.

Atmospheric Pressure: This is the pressure exerted by the air around the container, which is the pressure of the surrounding atmosphere.

Gauge Pressure: This is the pressure of the gas inside the container relative to the atmospheric pressure. It can be found using the formula:

[tex]\[ \text{Gauge Pressure} = \text{Absolute Pressure} - \text{Atmospheric Pressure} \][/tex]

Given:
- Absolute pressure inside the container, [tex]\( P_{\text{absolute}} = 125.4 \)[/tex] kPa
- Atmospheric pressure, [tex]\( P_{\text{atmospheric}} = 99.8 \)[/tex] kPa

Now, substitute these values into the gauge pressure formula:

[tex]\[ \text{Gauge Pressure} = 125.4 \, \text{kPa} - 99.8 \, \text{kPa} = 25.6 \, \text{kPa} \][/tex]

Therefore, the gauge pressure inside the container is [tex]\( 25.6 \)[/tex] kPa.

The correct answer is:
C. [tex]\( 25.6 \)[/tex] kPa