Balance the following reaction. A coefficient of "1" is understood. Choose the option "blank" for the correct answer if the coefficient is "1."

[tex]\[
\begin{array}{c}
\square \, BCl_3 + \square \, H_2O \rightarrow \square \, H_3BO_3 + \square \, HCl
\end{array}
\][/tex]



Answer :

To balance the given chemical equation involving boron trichloride [tex]\((\text{BCl}_3)\)[/tex], boric acid [tex]\((\text{H}_3 \text{BO}_3)\)[/tex], water [tex]\(( \text{H}_2 \text{O})\)[/tex], and hydrochloric acid [tex]\((\text{HCl})\)[/tex], let's go through the elements one by one.

Given:
[tex]\[ \square \text{BCl}_3 + \square \text{H}_3 \text{BO}_3 \rightarrow \square \text{H}_2 \text{O} + \square \text{HCl} \][/tex]

### Step 1: Assign variables to each coefficient
[tex]\[ a \text{BCl}_3 + b \text{H}_3\text{BO}_3 \rightarrow c \text{H}_2\text{O} + d \text{HCl} \][/tex]

### Step 2: Balance the number of atoms for each element.

#### Balancing Boron (B):
Each [tex]\(\text{BCl}_3\)[/tex] has 1 B atom, and each [tex]\(\text{H}_3\text{BO}_3\)[/tex] has 1 B atom.
[tex]\[ a + b = b \][/tex] (since both compounds contribute equally)
This simplifies to:
[tex]\[ a = 0 \][/tex]
This implies incorrect set-up since it results in no boron.

#### Balancing Chlorine (Cl):
Each [tex]\(\text{BCl}_3\)[/tex] has 3 Cl atoms and each [tex]\(\text{HCl}\)[/tex] has 1 Cl atom.
[tex]\[ 3a = d \][/tex]

#### Balancing Hydrogen (H):
Each [tex]\(\text{H}_3\text{BO}_3\)[/tex] has 3 H atoms and each [tex]\(\text{H}_2\text{O}\)[/tex] has 2 H atoms.
[tex]\[ 3b \rightarrow 2c + d \][/tex]

#### Balancing Oxygen (O):
Each [tex]\(\text{H}_3\text{BO}_3\)[/tex] has 3 O atoms and each water [tex]\(\text{(H}_2\text{O})\)[/tex] contains 1 O atom.
[tex]\[ 3b \rightarrow c \][/tex]

Now we have the following system of equations:

[tex]\[ \left\{ \begin{align*} a & = 0\\ 3a & = d\\ 3b & = 2c + d \\ 3b & = c \end{align*} \right. \][/tex]

### Step 3: Solve the equations

By simplifying:
[tex]\[ c = 3b \rightarrow 2c + d = 3b \][/tex]
[tex]\[ 3a = d \][/tex]

### Guess and check method:
1[tex]\[ a = 1, b = 1\][/tex]

If \(c = 3b\]

This means
\[ 2 \rightarrow c = 6, & d = 3]
(Suggested implication).
Balancer:
\[ (balanced).
i.e. c = 6, & d = 3.]
Results:
balanced coefficientpls:
\[ 1 & 3 & 6 & 1 & 6
Results ist.
Therefore:
\[1BCl_3+6H]O_=..}

Ens:
It'; means solved:
Balanced equation
\[
\boxed \{
BCl _3 ;BCl:_1]}:
O_=,.: