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Drag each quantity to the correct location on the table.

Complete the table of bond energies and bond lengths.

[tex]125 \, \text{pm} \quad 145 \, \text{pm} \quad 167 \, \text{kJ/mol} \quad 942 \, \text{kJ/mol} \quad 110 \, \text{pm} \quad 418 \, \text{kJ/mol}[/tex]

\begin{tabular}{|l|l|l|}
\hline & \text{Bond Energy} & \text{Bond Length} \\
\hline [tex]$N - N$[/tex] & & \\
\hline [tex]$N = N$[/tex] & & \\
\hline [tex]$N \equiv N$[/tex] & & \\
\hline
\end{tabular}



Answer :

GinnyAnswer
Sure, let's complete the table with the given quantities.

From the analysis:

- The [tex]\( N-N \)[/tex] single bond has a bond energy of 167 kJ/mol and a bond length of 145 pm.
- The [tex]\( N=N \)[/tex] double bond has a bond energy of 418 kJ/mol and a bond length of 125 pm.
- The [tex]\( N \equiv N \)[/tex] triple bond has a bond energy of 942 kJ/mol and a bond length of 110 pm.

Now, let's place these values into the table:

[tex]\[ \begin{tabular}{|l|l|l|} \hline & Bond Energy & Bond Length \\ \hline $N - N$ & 167 kJ/mol & 145 pm \\ \hline $N = N$ & 418 kJ/mol & 125 pm \\ \hline $N \equiv N$ & 942 kJ/mol & 110 pm \\ \hline \end{tabular} \][/tex]

So, the table is now complete with correct values for bond energies and bond lengths for single, double, and triple nitrogen bonds.

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