Brian is solving the equation [tex]$x^2-\frac{3}{4} x=5$[/tex]. What value must be added to both sides of the equation to make the left side a perfect-square trinomial?

A. [tex]\frac{9}{64}[/tex]
B. [tex]\frac{9}{16}[/tex]
C. [tex]\frac{3}{4}[/tex]
D. [tex]\frac{9}{4}[/tex]



Answer :

Let's solve the problem step-by-step.

1. Original Equation:
[tex]\[ x^2 - \frac{3}{4}x = 5 \][/tex]

2. Identify the coefficient of [tex]\(x\)[/tex]:
The coefficient of [tex]\(x\)[/tex] is [tex]\(-\frac{3}{4}\)[/tex].

3. Determine the value to add:
To transform the left side of the equation into a perfect-square trinomial, we need to add [tex]\(\left(\frac{b}{2}\right)^2\)[/tex] to both sides, where [tex]\(b\)[/tex] is the coefficient of [tex]\(x\)[/tex].

4. Calculate [tex]\(\left(\frac{b}{2}\right)^2\)[/tex]:
Here, [tex]\(b = -\frac{3}{4}\)[/tex]. Thus,
[tex]\[ \left(\frac{b}{2}\right)^2 = \left(\frac{-\frac{3}{4}}{2}\right)^2 \][/tex]

5. Simplify the calculation:
[tex]\[ \left(\frac{-\frac{3}{4}}{2}\right)^2 = \left(-\frac{3}{4} \cdot \frac{1}{2}\right)^2 = \left(-\frac{3}{8}\right)^2 = \frac{9}{64} \][/tex]

6. Conclusion:
The value that must be added to both sides of the equation to make the left side a perfect-square trinomial is [tex]\(\frac{9}{64}\)[/tex].

Hence, the correct answer is:
[tex]\[ \boxed{\frac{9}{64}} \][/tex]