Alright, let's go through this step-by-step to answer all parts of the question.
### Understanding Acidity of a Base
The term "acidity of a base" might seem counterintuitive. However, in some contexts, it refers to the concept of the base behaving like an acid in terms of its capacity to react and neutralize the acidic properties of another compound. Essentially, it's about how the base interacts with acids.
### Mixing of Na2CO3 and H2SO4
We have two solutions being mixed:
1. Sodium carbonate (Na2CO3):
- Volume: 500 cc (or 0.5 liters)
- Normality: 2 N
2. Sulfuric acid (H2SO4):
- Volume: 400 cc (or 0.4 liters)
- Normality: 3 N
We need to determine if the resulting solution is acidic, basic, or neutral after mixing and diluting to one liter.
#### Step 1: Calculate the milliequivalents of each solution
- Milliequivalents of Na2CO3 = Volume (in cc) × Normality
- [tex]\( = 500 \text{ cc} \times 2 \text{ N} \)[/tex]
- [tex]\( = 1000 \text{ milliequivalents} \)[/tex]
- Milliequivalents of H2SO4 = Volume (in cc) × Normality
- [tex]\( = 400 \text{ cc} \times 3 \text{ N} \)[/tex]
- [tex]\( = 1200 \text{ milliequivalents} \)[/tex]
#### Step 2: Determine the excess milliequivalents
- To determine if the solution is acidic, basic, or neutral, we compare the milliequivalents:
- Excess milliequivalents = Milliequivalents of H2SO4 - Milliequivalents of Na2CO3
- [tex]\( = 1200 - 1000 \)[/tex]
- [tex]\( = 200 \text{ excess milliequivalents} \)[/tex]
Since we have excess milliequivalents of H2SO4, the solution will be acidic.
### Step 3: Calculate the molarity of the resulting solution
To find the molarity, we need to consider the final dilution to one liter and the equivalent factor for the acid.
- Normality (N) = Molarity (M) × Equivalents
- For H2SO4 (diprotic acid), the equivalents factor is 2.
Now, calculate the molarity:
- Molarity = Excess milliequivalents / (final volume × equivalents factor)
- [tex]\( = \frac{200}{1000 \text{ cc} \times 2} \)[/tex]
- [tex]\( = \frac{200}{2000} \)[/tex]
- [tex]\( = 0.1 \text{ M} \)[/tex]
### Summary of Answers:
1. Acidity of Base: It refers to the concept of a base reacting with an acid.
2. Nature of the Resulting Solution: The resulting solution is acidic.
3. Molarity of Dilute Solution: The molarity of the dilute solution is 0.1 M.
Therefore, the final detailed, step-by-step solution confirms that the resulting solution, after mixing and dilution to one liter, will be acidic with a molarity of 0.1 M.
