Watch the video and then solve the problem given below.

In a town whose population is 3400, a disease creates an epidemic. The number of people [tex]\( N(t) \)[/tex] infected [tex]\( t \)[/tex] days after the disease has begun is given by the function:

[tex]\[ N(t) = \frac{3400}{1 + 24.8 e^{-0.7t}} \][/tex]

Complete parts (a) through (c) below.

a) How many are initially infected with the disease ([tex]\( t = 0 \)[/tex])?

[tex]\[ \boxed{} \][/tex] (Round to the nearest whole number as needed.)



Answer :

Certainly! Let's solve the problem step-by-step, using the function provided to determine the number of people initially infected when [tex]\( t = 0 \)[/tex].

The function given is:
[tex]\[ N(t) = \frac{3400}{1 + 24.8 e^{-0.7 t}} \][/tex]

### Step-by-Step Solution:

1. Identify the Initial Condition:
We need to find the initial number of infected people, which means evaluating [tex]\( N(t) \)[/tex] at [tex]\( t = 0 \)[/tex].

2. Substitute [tex]\( t = 0 \)[/tex] Into the Function:
Plugging [tex]\( t = 0 \)[/tex] into the function, we get:
[tex]\[ N(0) = \frac{3400}{1 + 24.8 e^{-0.7 \cdot 0}} \][/tex]

3. Simplify the Exponential Term:
Since any number raised to the power of zero is 1:
[tex]\[ e^{0} = 1 \][/tex]

4. Simplify the Denominator:
Substituting [tex]\( e^{0} = 1 \)[/tex] into the denominator, we get:
[tex]\[ 1 + 24.8 \cdot 1 = 1 + 24.8 = 25.8 \][/tex]

5. Calculate the Initial Number of Infected People [tex]\( N(0) \)[/tex]:
Now, we simply divide the population by this number:
[tex]\[ N(0) = \frac{3400}{25.8} \][/tex]

6. Perform the Division:
Divide 3400 by 25.8 to find the initial number of infected people:
[tex]\[ N(0) = 131.78 \][/tex]

7. Round to the Nearest Whole Number:
Since we are asked to round to the nearest whole number:
[tex]\[ N(0) \approx 132 \][/tex]

### Conclusion:
So, the number of people initially infected with the disease when [tex]\( t = 0 \)[/tex] is [tex]\( \boxed{132} \)[/tex].