What is the perimeter of a polygon with vertices at [tex]$(-2,1)$[/tex], [tex]$(-2,7)$[/tex], [tex]$(1,11)$[/tex], [tex]$(4,7)$[/tex], and [tex]$(4,1)$[/tex]?

Enter your answer in the box. Do not round any side lengths.

[tex]\[\square \text{ units}\][/tex]



Answer :

To find the perimeter of the given polygon with vertices at [tex]\((-2,1)\)[/tex], [tex]\((-2,7)\)[/tex], [tex]\((1,11)\)[/tex], [tex]\((4,7)\)[/tex], and [tex]\((4,1)\)[/tex], we will follow these steps:

1. Calculate the lengths of each side using the distance formula:

The distance formula to find the distance between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is:
[tex]\[ \text{Distance} = \sqrt{{(x_2 - x_1)^2 + (y_2 - y_1)^2}} \][/tex]

Side 1: Between [tex]\((-2,1)\)[/tex] and [tex]\((-2,7)\)[/tex]
[tex]\[ \text{distance} = \sqrt{{(-2 - (-2))^2 + (7 - 1)^2}} = \sqrt{{0 + 6^2}} = \sqrt{{36}} = 6 \][/tex]

Side 2: Between [tex]\((-2,7)\)[/tex] and [tex]\((1,11)\)[/tex]
[tex]\[ \text{distance} = \sqrt{{(1 - (-2))^2 + (11 - 7)^2}} = \sqrt{{3^2 + 4^2}} = \sqrt{{9 + 16}} = \sqrt{{25}} = 5 \][/tex]

Side 3: Between [tex]\((1,11)\)[/tex] and [tex]\((4,7)\)[/tex]
[tex]\[ \text{distance} = \sqrt{{(4 - 1)^2 + (7 - 11)^2}} = \sqrt{{3^2 + (-4)^2}} = \sqrt{{9 + 16}} = \sqrt{{25}} = 5 \][/tex]

Side 4: Between [tex]\((4,7)\)[/tex] and [tex]\((4,1)\)[/tex]
[tex]\[ \text{distance} = \sqrt{{(4 - 4)^2 + (1 - 7)^2}} = \sqrt{{0 + (-6)^2}} = \sqrt{{36}} = 6 \][/tex]

Side 5: Between [tex]\((4,1)\)[/tex] and [tex]\((-2,1)\)[/tex]
[tex]\[ \text{distance} = \sqrt{{(4 - (-2))^2 + (1 - 1)^2}} = \sqrt{{6^2 + 0}} = \sqrt{{36}} = 6 \][/tex]

2. Sum the lengths of all the sides to find the perimeter:

[tex]\[ \text{Perimeter} = 6 + 5 + 5 + 6 + 6 = 28 \][/tex]

So, the perimeter of the polygon is [tex]\(28\)[/tex] units.

Thus, the answer is:
[tex]\[ \boxed{28} \][/tex]