Solve the compound inequality for [tex] x [/tex]:

[tex]\[ 8 \ \textgreater \ 3x - 1 \ \textgreater \ 5 \][/tex]

Select one:
a. [tex]\[ \frac{7}{3} \ \textgreater \ x \ \textgreater \ \frac{4}{3} \][/tex]
b. [tex]\[ 3 \ \textgreater \ x \ \textgreater \ 2 \][/tex]
c. [tex]\[ 12 \ \textless \ x \ \textless \ 28 \][/tex]
d. [tex]\[ 27 \ \textgreater \ x \ \textgreater \ 18 \][/tex]



Answer :

To solve the compound inequality [tex]\(8 > 3x - 1 > 5\)[/tex], we will break it down into two separate inequalities and solve each one step by step.

### Step 1: Break Down the Inequality
The given compound inequality can be separated into two individual inequalities:
1. [tex]\(8 > 3x - 1\)[/tex]
2. [tex]\(3x - 1 > 5\)[/tex]

### Step 2: Solve the First Inequality

Inequality 1: [tex]\(8 > 3x - 1\)[/tex]

1. Add 1 to both sides to isolate the term involving [tex]\(x\)[/tex]:
[tex]\[ 8 + 1 > 3x - 1 + 1 \][/tex]
2. Simplify:
[tex]\[ 9 > 3x \][/tex]
3. Divide both sides by 3 to solve for [tex]\(x\)[/tex]:
[tex]\[ \frac{9}{3} > x \][/tex]
4. Simplify:
[tex]\[ 3 > x \quad \text{or} \quad x < 3 \][/tex]

### Step 3: Solve the Second Inequality

Inequality 2: [tex]\(3x - 1 > 5\)[/tex]

1. Add 1 to both sides to isolate the term involving [tex]\(x\)[/tex]:
[tex]\[ 3x - 1 + 1 > 5 + 1 \][/tex]
2. Simplify:
[tex]\[ 3x > 6 \][/tex]
3. Divide both sides by 3 to solve for [tex]\(x\)[/tex]:
[tex]\[ x > \frac{6}{3} \][/tex]
4. Simplify:
[tex]\[ x > 2 \][/tex]

### Step 4: Combine the Results

We have found two inequalities:
- [tex]\(x < 3\)[/tex]
- [tex]\(x > 2\)[/tex]

Combining these two gives:
[tex]\[ 2 < x < 3 \][/tex]

### Final Answer
The correct option is:

b. [tex]\(3 > x > 2\)[/tex] or equivalently [tex]\(2 < x < 3\)[/tex]