Nick has a bag of marbles. Without looking in the bag, he selects a marble, records its color, and puts it back in the bag. All marbles are equally likely to be chosen. He performs 100 trials.

\begin{tabular}{|l|l|}
\hline
Number of times a white marble was chosen & 48 \\
\hline
Number of times a red marble was chosen & 13 \\
\hline
Number of times a green marble was chosen & 27 \\
\hline
Number of times a blue marble was chosen & 12 \\
\hline
\end{tabular}

Based on the data Nick collected, what is the estimated probability, in simplest form, of choosing a white marble from the bag?

A. [tex]$\frac{12}{25}$[/tex]

B. [tex]$\frac{12}{100}$[/tex]

C. [tex]$\frac{50}{24}$[/tex]

D. [tex]$\frac{48}{100}$[/tex]



Answer :

To find the estimated probability of choosing a white marble from the bag, follow these steps:

1. Determine the number of times a white marble was chosen: According to the data, Nick chose a white marble 48 times out of the total trials.

2. Determine the total number of trials: The problem states that he performed 100 trials in total.

3. Calculate the probability: The probability [tex]\( P \)[/tex] of choosing a white marble is the number of times a white marble was chosen divided by the total number of trials. Therefore,
[tex]\[ P(\text{white}) = \frac{\text{Number of times a white marble was chosen}}{\text{Total number of trials}} \][/tex]
which gives us:
[tex]\[ P(\text{white}) = \frac{48}{100} \][/tex]

4. Simplify the fraction: To simplify [tex]\(\frac{48}{100}\)[/tex], we need to find the greatest common divisor (GCD) of 48 and 100.

- The GCD of 48 and 100 is 4.

So, divide both the numerator and the denominator by 4:
[tex]\[ \frac{48 \div 4}{100 \div 4} = \frac{12}{25} \][/tex]

So, the estimated probability of choosing a white marble from the bag, in its simplest form, is [tex]\(\frac{12}{25}\)[/tex].

The correct answer is:
A. [tex]\(\frac{12}{25}\)[/tex]