To determine the estimated probability that Harriet will eat pizza for lunch every day next week, we start by analyzing each group of random digits given in the simulation. The digits that represent the availability of pizza are 2 through 9, while digits 0 and 1 indicate no pizza available. Harriet will eat pizza every day next week only if all the digits in a group's sequence are between 2 and 9.
To solve this, we can follow these steps:
1. Check each group of digits to ensure they contain only the digits 2 through 9, as these represent days when pizza is available. Here are the groups and their validity:
- Group 1: "19223" (Contains digit 1; not valid)
- Group 2: "73676" (All digits are 2-9; valid)
- Group 3: "45467" (All digits are 2-9; valid)
- Group 4: "52711" (Contains digit 1; not valid)
- Group 5: "95592" (All digits are 2-9; valid)
- Group 6: "68417" (Contains digit 1; not valid)
- Group 7: "82739" (All digits are 2-9; valid)
- Group 8: "60940" (Contains digits 0; not valid)
- Group 9: "36009" (Contains digit 0; not valid)
- Group 10: "38448" (All digits are 2-9; valid)
2. Count how many groups have all digits between 2 and 9.
From the analysis above, Groups 2, 3, 5, 7, and 10 are all valid. So, there are 5 valid groups in total.
3. Calculate the total number of groups.
There are 10 groups in total.
4. Determine the estimated probability.
The probability is the ratio of the number of valid groups to the total number of groups:
[tex]\[
\text{Probability} = \frac{\text{Number of valid groups}}{\text{Total number of groups}} = \frac{5}{10} = 0.5
\][/tex]
Therefore, the estimated probability that Harriet will eat pizza every day next week is [tex]\(0.5\)[/tex] or [tex]\(50\%\)[/tex].
Based on this solution, none of the provided answer choices (A, B, C) are correct. However, if there are typographical errors in question options, the correct response should be [tex]\(50\%\)[/tex] or probability [tex]\(0.5\)[/tex].
