Answered

A group of 163 doctors and nurses volunteered to run a health fair. Each volunteer worked one shift. The table below summarizes the data on the volunteers and their shifts.

\begin{tabular}{|l|c|c|c|}
\cline { 2 - 4 }
\multicolumn{1}{c|}{} & Morning & Afternoon & Evening \\
\hline
Doctor & 36 & 59 & 7 \\
\hline
Nurse & 11 & 42 & 8 \\
\hline
\end{tabular}

Suppose a volunteer from the health fair is chosen at random. Answer each part. Do not round intermediate computations, and round your answers to the nearest hundredth.

(a) What is the probability that the volunteer is a doctor, given that the volunteer worked the morning shift?
[tex]\[ \square \][/tex]

(b) What is the probability that the volunteer is a nurse or worked the afternoon shift?
[tex]\[ \square \][/tex]



Answer :

Let's solve each part of the question step-by-step.

### Part (a)

We need to determine the probability that a randomly selected volunteer is a doctor, given that the volunteer worked the morning shift.

Step 1: Identify the number of doctors and nurses for each shift from the table:
- Morning Doctors: 36
- Morning Nurses: 11

Step 2: Calculate the total number of volunteers who worked the morning shift:
[tex]\[ \text{Total Morning Volunteers} = \text{Morning Doctors} + \text{Morning Nurses} = 36 + 11 = 47 \][/tex]

Step 3: The conditional probability [tex]\(P(\text{Doctor}|\text{Morning})\)[/tex] is calculated as the number of doctors in the morning divided by the total number of volunteers in the morning shift:
[tex]\[ P(\text{Doctor}|\text{Morning}) = \frac{\text{Morning Doctors}}{\text{Total Morning Volunteers}} = \frac{36}{47} \][/tex]

Step 4: Compute the probability and round to the nearest hundredth:
[tex]\[ P(\text{Doctor}|\text{Morning}) \approx 0.77 \][/tex]

Thus, the probability that the volunteer is a doctor given that the volunteer worked the morning shift is approximately [tex]\(0.77\)[/tex].

### Part (b)

We need to determine the probability that the volunteer is a nurse or worked the afternoon shift.

Step 1: Identify the total number of each type and shift from the table:
- Total Volunteers: 163
- Total Nurses: 11 (morning) + 42 (afternoon) + 8 (evening) = 61
- Total Afternoon Volunteers: 59 (doctors) + 42 (nurses) = 101
- Afternoon Nurses: 42

Step 2: Compute the probability of being a nurse:
[tex]\[ P(\text{Nurse}) = \frac{\text{Total Nurses}}{\text{Total Volunteers}} = \frac{61}{163} \][/tex]

Step 3: Compute the probability of working the afternoon shift:
[tex]\[ P(\text{Afternoon}) = \frac{\text{Total Afternoon Volunteers}}{\text{Total Volunteers}} = \frac{101}{163} \][/tex]

Step 4: Compute the probability of being a nurse and working the afternoon shift (which is the event intersection):
[tex]\[ P(\text{Nurse and Afternoon}) = \frac{\text{Afternoon Nurses}}{\text{Total Volunteers}} = \frac{42}{163} \][/tex]

Step 5: Use the formula for the union of two probabilities:
[tex]\[ P(\text{Nurse or Afternoon}) = P(\text{Nurse}) + P(\text{Afternoon}) - P(\text{Nurse and Afternoon}) \][/tex]

[tex]\[ P(\text{Nurse or Afternoon}) = \frac{61}{163} + \frac{101}{163} - \frac{42}{163} \][/tex]

Step 6: Calculate the final probability and round to the nearest hundredth:
[tex]\[ P(\text{Nurse or Afternoon}) \approx 0.74 \][/tex]

Thus, the probability that the volunteer is a nurse or worked the afternoon shift is approximately [tex]\(0.74\)[/tex].