To determine how many moles of zinc oxide (ZnO) will be consumed when 0.757 moles of hydrochloric acid (HCl) react with it, we need to refer to the balanced chemical equation for the reaction:
[tex]\[ \text{ZnO} + 2\text{HCl} \longrightarrow \text{ZnCl}_2 + \text{H}_2\text{O} \][/tex]
From this balanced equation, we can see that 1 mole of zinc oxide (ZnO) reacts with 2 moles of hydrochloric acid (HCl).
Given:
- Moles of HCl provided = 0.757 moles
We need to find how many moles of ZnO are consumed. According to the stoichiometric ratios from the balanced equation, for every 2 moles of HCl, 1 mole of ZnO is used.
To find the number of moles of ZnO consumed, we use the stoichiometric relationship:
[tex]\[ \text{moles of ZnO} = \frac{\text{moles of HCl}}{2} \][/tex]
Substituting the given value:
[tex]\[ \text{moles of ZnO} = \frac{0.757 \, \text{moles}}{2} \][/tex]
[tex]\[ \text{moles of ZnO} = 0.3785 \, \text{moles} \][/tex]
Therefore, 0.3785 moles of zinc oxide will be consumed when 0.757 moles of hydrochloric acid react with it.
