Answer:
[tex]y = -\frac{9}{11} x -9[/tex]
Step-by-step explanation:
To find the equation of a line with slope m = -9/11 that goes through the point (−11,0), we use the point-slope form of the equation of a line:
[tex]y-y_{1} = m(x -x_{1} )[/tex]
Here, [tex]m=-\frac{9}{11}, x_{1} = -11, y_{1}=0[/tex]
Substitute these values into the point-slope form:
[tex]y-0=-\frac{9}{11} (x-(-11))[/tex]
[tex]y= -\frac{9}{11} (x+11)[/tex]
Next, distribute the [tex]\frac{9}{11}[/tex]
[tex]y = -\frac{9}{11} x + -\frac{9}{11} *11[/tex]
[tex]y = -\frac{9}{11} x -9[/tex]
And BOOM you get your answer. So, the equation of the line is:
[tex]y = -\frac{9}{11} x -9[/tex]
Brainly please :3
