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Tall height is a dominant trait in pea plants. In these Punnett squares, T denotes tall and t denotes short. What can you conclude from these Punnett squares?

\begin{tabular}{|c|c|c|}
\hline \multicolumn{3}{|c|}{ F1 Generation } \\
\hline & t & t \\
\hline T & Tt & Tt \\
\hline T & Tt & Tt \\
\hline \multicolumn{3}{|c|}{ F2 Generation } \\
\hline & T & t \\
\hline T & TT & Tt \\
\hline t & Tt & tt \\
\hline
\end{tabular}

A. All short plants are homozygous for that trait.
B. All tall plants are homozygous for that trait.
C. Both parents in F1 are homozygous dominant.
D. Both parents in F2 are heterozygous.



Answer :

GinnyAnswer
Certainly! Let's go through the problem step by step based on the information provided:

### F1 Generation Punnett Square
The F1 generation Punnett square shows the following cross:
```
t t
T Tt Tt
T Tt Tt
```

Analysis:
- The parents have genotypes Tt and Tt (both are heterozygous).
- The resulting offspring genotypes are all Tt, which are tall since the T allele (tall) is dominant.

### F2 Generation Punnett Square
The F2 generation Punnett square shows the following cross:
```
T t
T TT Tt
t Tt tt
```

Analysis:
- One parent has genotype TT (homozygous dominant) and the other has genotype Tt (heterozygous).
- The resulting offspring genotypes are:
- TT (homozygous dominant) - tall
- Tt (heterozygous) - tall
- tt (homozygous recessive) - short

### Conclusion from provided options:
1. All short plants are homozygous for that trait.
- This is a correct statement because short plants have the genotype tt, which is homozygous recessive.
2. All tall plants are homozygous for that trait.
- This is incorrect because tall plants can be either TT (homozygous dominant) or Tt (heterozygous).
3. Both parents in F1 are homozygous dominant.
- This is incorrect because the parents in F1 are heterozygous (Tt).
4. Both parents in F2 are heterozygous.
- This is incorrect because the parents in F2 are TT (homozygous dominant) and Tt (heterozygous).

Therefore, the correct conclusion is:

All short plants are homozygous for that trait.

This means the correct answer is option 1.

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