Certainly! Let's address each part of the question in detail.
### Part (a)
Question: In which group do the elements having electronic configuration [tex]\(1s^2 2s^2 2p^3\)[/tex] lie?
Given Options:
a. III A
b. III B
c. V A
d. VB
#### Solution:
- First, we analyze the given electronic configuration: [tex]\(1s^2 2s^2 2p^3\)[/tex].
- The notation tells us:
- [tex]\(1s^2\)[/tex]: 2 electrons in the 1s orbital.
- [tex]\(2s^2\)[/tex]: 2 electrons in the 2s orbital.
- [tex]\(2p^3\)[/tex]: 3 electrons in the 2p orbitals.
- Summing up, [tex]\(2 + 2 + 3 = 7\)[/tex] electrons in total.
- This corresponds to the element nitrogen (N) which has an atomic number of 7.
- In the periodic table, nitrogen belongs to Group 15 (using the IUPAC nomenclature), which is equivalently Group V A in older notation systems (considering the given options).
Therefore, the correct answer is:
c. V A
### Part (b)
Question: What are the elements between groups IIA and IIIA called?
Groups from the periodic table tutorial:
- Group IIA corresponds to the Alkaline Earth Metals.
- Group IIIA corresponds to the Boron Group.
#### Solution:
- The elements lying between group IIA (2) and group IIIA (13) fall under the transition metals category.
- These elements reside in the d-block of the periodic table and possess properties typical of transition elements (such as multiple oxidation states, formation of colored compounds, etc.).
Therefore, the correct term for elements lying between groups IIA and IIIA is:
transition elements
### Full Answer:
1. (a) In which group do the elements having electronic configuration [tex]\(1s^2, 2s^2, 2p^3\)[/tex] lie?
- Correct option: c. V A
(b) What are the elements between groups IIA and IIIA called?
- Answer: transition elements
