To find the molar mass of sulfur hexafluoride ([tex]$SF_6$[/tex]), we need to consider the contributions of both the sulfur (S) atom and the six fluorine (F) atoms present in one molecule of [tex]$SF_6$[/tex].
1. Identify the molar masses of the individual elements: - The molar mass of sulfur (S) is approximately 32.06 g/mol. - The molar mass of fluorine (F) is approximately 18.998 g/mol.
2. Calculate the total contribution of the fluorine atoms: - Since there are six fluorine atoms in each molecule of [tex]$SF_6$[/tex], we multiply the molar mass of fluorine by 6. - Contribution from fluorine = [tex]$6 \times 18.998$[/tex] g/mol.
3. Add the contributions from sulfur and fluorine to get the molar mass of [tex]$SF_6$[/tex]: - Total molar mass of [tex]$SF_6 = 32.06$[/tex] g/mol (from sulfur) [tex]$+ 6 \times 18.998$[/tex] g/mol (from fluorine). - Total molar mass = [tex]$32.06 + 113.988 = 146.048$[/tex] g/mol.
4. Round the result to the nearest hundredth place: - The molar mass of sulfur hexafluoride ([tex]$SF_6$[/tex]) rounded to the nearest hundredth is [tex]$146.05$[/tex] g/mol.
Therefore, the molar mass of [tex]$SF_6$[/tex] is 146.05 g/mol.
