Original:
y varies directly with x . [tex]$y$[/tex] is 30 when [tex]$x$[/tex] is 6 . What is the value of k ?
[tex]$ y=[?] x $[/tex]

Formatted:

Given that [tex]\( y \)[/tex] varies directly with [tex]\( x \)[/tex] and [tex]\( y \)[/tex] is 30 when [tex]\( x \)[/tex] is 6, what is the value of [tex]\( k \)[/tex]?

[tex]\[ y = kx \][/tex]



Answer :

To solve the problem where [tex]\( y \)[/tex] varies directly with [tex]\( x \)[/tex] and we need to find the constant of variation ([tex]\( k \)[/tex]), we start by using the relationship for direct variation:

[tex]\[ y = k \cdot x \][/tex]

Given:
- [tex]\( y = 30 \)[/tex]
- [tex]\( x = 6 \)[/tex]

Substitute these values into the direct variation equation:

[tex]\[ 30 = k \cdot 6 \][/tex]

To find [tex]\( k \)[/tex], isolate [tex]\( k \)[/tex] by dividing both sides of the equation by 6:

[tex]\[ k = \frac{30}{6} \][/tex]

Simplify the fraction:

[tex]\[ k = 5 \][/tex]

Therefore, the value of [tex]\( k \)[/tex] is 5.