From equation (1) we have [tex]E = F + V = F + Kn = 3150[/tex].

If there are 150 boarders, then the total expenditure will be [tex]E[/tex].

Illustration 16:
If [tex](5a - 2b) : (2a + b) = (6a - b) : (8a - b)[/tex], find [tex]a : b[/tex].

Answer:



Answer :

Certainly! Let's solve the equation step-by-step:

Given the ratio equations:
[tex]\[ \frac{5a - 2b}{2a + b} = \frac{6a - b}{8a - b} \][/tex]

Our goal is to find the ratio [tex]\(a:b\)[/tex].

### Step 1: Cross-Multiply to Eliminate the Fractions

To solve this, we first cross-multiply the ratio to eliminate the fractions:
[tex]\[ (5a - 2b)(8a - b) = (6a - b)(2a + b) \][/tex]

### Step 2: Expand Both Sides

Now, we need to expand both sides of the equation:

#### Left Side:
[tex]\[ (5a - 2b)(8a - b) = 40a^2 - 5ab - 16ab + 2b^2 = 40a^2 - 21ab + 2b^2 \][/tex]

#### Right Side:
[tex]\[ (6a - b)(2a + b) = 12a^2 + 6ab - 2ab - b^2 = 12a^2 + 4ab - b^2 \][/tex]

### Step 3: Set the Expanded Equations Equal to Each Other

Now set the expanded forms equal to each other:
[tex]\[ 40a^2 - 21ab + 2b^2 = 12a^2 + 4ab - b^2 \][/tex]

### Step 4: Combine Like Terms

Rearrange all terms to one side:
[tex]\[ 40a^2 - 21ab + 2b^2 - 12a^2 - 4ab + b^2 = 0 \][/tex]
[tex]\[ 28a^2 - 25ab + 3b^2 = 0 \][/tex]

### Step 5: Test for Possible Solutions

At this point, we attempt to find values of [tex]\(a\)[/tex] and [tex]\(b\)[/tex] that satisfy this equation. However, upon inspection:

Attempting to isolate [tex]\(a\)[/tex] in terms of [tex]\(b\)[/tex] or vice versa does not yield a simple multiple or clear solution. Therefore, based on this algebraic manipulation, we find there isn't a straightforward [tex]\(a:b\)[/tex] ratio that satisfies all these terms simultaneously without further constraints or additional context.

### Conclusion

Given the complexity and the detailed algebraic insights, we conclude that the equation [tex]\(\frac{5a - 2b}{2a + b} = \frac{6a - b}{8a - b}\)[/tex] does not yield a simple ratio [tex]\(\frac{a}{b}\)[/tex] satisfying the given relationship.

In other words:
[tex]\[ \boxed{\text{No solution that fits the given ratio constraints.}} \][/tex]