Look at the table below. Rewrite the mass for the fourth object in scientific notation.

\begin{tabular}{|l|l|}
\hline Object & Mass (s) \\
\hline 1 & 0.0012 \\
\hline 2 & 35.090 \\
\hline 3 & 0.0000008 \\
\hline 4 & [tex]$6,084,000$[/tex] \\
\hline 5 & 700.00 \\
\hline
\end{tabular}

A. [tex]$6.084 \times 10^6$[/tex]
B. [tex]$6.084 \times 10^{-3}$[/tex]
C. [tex]$6.084 \times 10^3$[/tex]
D. [tex]$6.084 \times 10^{-6}$[/tex]



Answer :

Let's rewrite the mass of the fourth object, which is [tex]\(6,084,000\)[/tex], in scientific notation.

Scientific notation is a way of expressing numbers that are too large or too small to be conveniently written in decimal form. It is expressed as a number [tex]\(a \times 10^n\)[/tex] where [tex]\(1 \leq a < 10\% and \(n\)[/tex] is an integer.

Here are the steps to transform the number [tex]\(6,084,000\)[/tex] into scientific notation:

1. Identify the most significant digits of the number. In this case, the most significant digits are [tex]\(6.084\)[/tex].

2. Count how many places the decimal point must move to turn the original number into a number between 1 and 10. For [tex]\(6,084,000\)[/tex], the decimal point moves six places to the left.

Thus, [tex]\(6,084,000\)[/tex] becomes [tex]\(6.084\)[/tex].

3. The number of places you moved the decimal point becomes the exponent of 10. Since we moved the decimal point six places to the left, the exponent is 6.

Combining these, the mass of the fourth object in scientific notation is:
[tex]\[ 6.084 \times 10^6 \][/tex]

Looking at the given options, the correct answer is:
A. [tex]\(6.084 \times 10^6\)[/tex]