Answer:
The answer depends on what the problem really is.
See below.
Step-by-step explanation:
The way this equation is written, it means this:
[tex] x + \dfrac{1}{2}x + 3 = \dfrac{3}{8} [/tex]
[tex] \dfrac{3}{2}x = \dfrac{3}{8} - \dfrac{24}{8} [/tex]
[tex] \dfrac{3}{2}x = -\dfrac{21}{8} [/tex]
[tex] x = -\dfrac{21}{8} \times \dfrac{2}[3} [/tex]
[tex] x = -\dfrac{7}{4} [/tex]
Perhaps you meant this:
[tex] \dfrac{x + 1}{2x + 3} = \dfrac{3}{8} [/tex]
Cross multiply.
[tex] 8(x + 1) = 3(2x + 3) [/tex]
[tex] 8x + 8 = 6x + 9 [/tex]
[tex] 2x = 1 [/tex]
[tex] x = \dfrac{1}{2} [/tex]
Please write problems clearly using fractions correctly and parentheses where needed, so there is no ambiguity.
