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How many protons, neutrons, and electrons are in this ion?
[tex]\[ ^{33}S^{2-} \][/tex]

A. [tex]\( 16 \, p^{+}, 33 \, n^{\circ}, 16 \, e^{-} \)[/tex]

B. [tex]\( 33 \, p^{+}, 16 \, n^{0}, 35 \, e^{-} \)[/tex]

C. [tex]\( 16 \, p^{+}, 17 \, n^{0}, 18 \, e^{-} \)[/tex]

D. [tex]\( 16 \, p^{+}, 17 \, n^{0}, 16 \, e^{-} \)[/tex]



Answer :

GinnyAnswer
To determine the number of protons, neutrons, and electrons in the ion [tex]\( \,^{33}S^{2-} \)[/tex], we need to consider the following information:

1. Protons: The number of protons in an element is defined by its atomic number. Sulfur (S) has an atomic number of 16, so it has 16 protons.

2. Neutrons: The number of neutrons is found by subtracting the atomic number from the mass number. The mass number here is given as 33. Therefore, the number of neutrons is:
[tex]\[ \text{Neutrons} = 33 - 16 = 17. \][/tex]

3. Electrons: In the neutral atom of sulfur, the number of electrons is equal to the number of protons, which is 16. However, the sulfur ion given is [tex]\( S^{2-} \)[/tex], meaning it has gained 2 additional electrons. Therefore, the number of electrons in [tex]\( S^{2-} \)[/tex] is:
[tex]\[ \text{Electrons} = 16 + 2 = 18. \][/tex]

Thus, the ion [tex]\( \,^{33}S^{2-} \)[/tex] has:
- 16 protons,
- 17 neutrons,
- 18 electrons.

So, the correct answer is:
[tex]\[ 16 \, p^+, 17 \, n^0, 18 \, e^- \][/tex]

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